苏州思科认证pk华为认证_苏州思科认证培训
来源：教育联展网 编辑：佚名 发布时间：2018-09-30
CCNP考试分为三门
CCNP新考试版本2.0: ROUTE路由300-101; SWITCH交换300-115; TSHOOT排错300-135;每科费用300美金,合计900美金
CCNP认证有效期为三年
如需要重新认证,必须在认证到期前**同级别考试中的任何一项,或**现在的CCE笔试,即可延续认证
【教学师资】
夏老师
从事IT教育行业7年，具备深厚的网络理 论知识。在互联网实施规划领域拥有专家级经验知识。擅长解决复杂的网络连接问题及灾难恢复，利用主流技术规划解决方案。主要负责思科 路由交换、安全，虚拟化等方向课程。有多年的教学经验，教学具有深入浅 出，教学方式多样化的特色，尤其在理论知识点在实际项目的应用思路，组合方式等，让学员真正达到“学以致用”。
CCIE路由交换笔试
考试代码: 400-101;考试费用: 450美元;考试时间: 140分钟;考试分数:满 分1000分, 804分**考试。
考试题型:单选题、多选题及拖图题,题量共100题。
考试地点:笔试部分考试在中国各个省会城市或一线城市基本都能考。
预约考试: CCIE笔试的预约可以**VUE 预约考位,报名学员将由老师统一安排预约考试(由于我们本身就是考场,预约时间可以跟随考生时间随时安排考试)
CCIE路由交换LAB考试
CCIE LAB考试时间为8小时,总分100分, CCIE LAB考试内容共分为三个模块
1) TS (Troubleshooting)故障排错总分24分,大于等于20分, pass
2) DIAG (Diagnose)故障诊断总分6分大于等于4分, pass
3) CFG (Configuration)配置总分70分,大于等于56分, pass
我们将为您提供考试的**新信息。 (lab的考试需要去北京或者香港,我们老 师会全程跟踪)
路由策略3：Distribute-list6在双点双向重分发中的应用
拓扑图：
如上图，在R2和R4上配置双点双向重发布，在配置双点双向重发布时，小AD重发布进大AD时是没问题的，但是大AD重发布进小AD时，就会出现问题，例如次优路径，环路等，如上图，如果是R2先学习到RIP网络的路由，那么在R4的路由表中，RIP网络的路由将是**OSPF学习到的，这样就产生了次优路径（不是**优的路由）！可以配置分发列表来避免次优路径！下面先不配置分发列表，查看各路由器的路由表，接下来好做实验：
配置参数：
R2:
router ospf 1
redistribute rip metric 12 subnets
network 2.2.2.0 0.0.0.255 area 0
router rip
version 2
redistribute ospf 1 metric 3
network 1.0.0.0
no auto-summary
R4:
router ospf 1
redistribute rip metric 12 subnets
network 4.4.4.0 0.0.0.255 area 0
router rip
version 2
redistribute ospf 1 metric 3
network 3.0.0.0
no auto-summary
查看路由表：
R1:
r1#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
C 1.1.1.0 is directly connected, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
R 2.2.2.0 [120/3] via 3.3.3.2, 00:00:11, Serial0/1
[120/3] via 1.1.1.2, 00:00:19, Serial0/0
3.0.0.0/24 is subnetted, 1 subnets
C 3.3.3.0 is directly connected, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
R 4.4.4.0 [120/3] via 3.3.3.2, 00:00:11, Serial0/1
[120/3] via 1.1.1.2, 00:00:19, Serial0/0
10.0.0.0/8 is variably subnetted, 7 subnets, 2 masks
R 10.10.10.10/32 [120/3] via 3.3.3.2, 00:00:11, Serial0/1
[120/3] via 1.1.1.2, 00:00:19, Serial0/0
R 10.11.11.11/32 [120/3] via 3.3.3.2, 00:00:13, Serial0/1
[120/3] via 1.1.1.2, 00:00:20, Serial0/0
R 10.8.8.8/32 [120/3] via 3.3.3.2, 00:00:13, Serial0/1
[120/3] via 1.1.1.2, 00:00:20, Serial0/0
R 10.9.9.9/32 [120/3] via 3.3.3.2, 00:00:13, Serial0/1
[120/3] via 1.1.1.2, 00:00:20, Serial0/0
C 10.2.0.0/16 is directly connected, Loopback1
C 10.3.0.0/16 is directly connected, Loopback2
C 10.1.0.0/16 is directly connected, Loopback0
r1#
可以看到R1学习到的OSPF的路由是**两台边界路由器R2和R4学习来的，而且实现了负载均衡。这里R2和R4是将OSPF重发布进RIP，是小AD重发布进大AD，不会出现问题。
R2:
r2#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
C 1.1.1.0 is directly connected, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
C 2.2.2.0 is directly connected, Serial0/1
3.0.0.0/24 is subnetted, 1 subnets
O E2 3.3.3.0 [110/12] via 2.2.2.1, 00:03:58, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
O 4.4.4.0 [110/128] via 2.2.2.1, 00:03:58, Serial0/1
10.0.0.0/8 is variably subnetted, 7 subnets, 2 masks
O 10.10.10.10/32 [110/65] via 2.2.2.1, 00:03:58, Serial0/1
O 10.11.11.11/32 [110/65] via 2.2.2.1, 00:03:58, Serial0/1
O 10.8.8.8/32 [110/65] via 2.2.2.1, 00:03:58, Serial0/1
O 10.9.9.9/32 [110/65] via 2.2.2.1, 00:03:58, Serial0/1
R 10.2.0.0/16 [120/1] via 1.1.1.1, 00:00:23, Serial0/0
R 10.3.0.0/16 [120/1] via 1.1.1.1, 00:00:23, Serial0/0
R 10.1.0.0/16 [120/1] via 1.1.1.1, 00:00:23, Serial0/0
r2#
可以看到R2**RIP学习到了RIP网络的路由！
R3:
r3#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
O E2 1.1.1.0 [110/12] via 2.2.2.2, 00:42:39, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
C 2.2.2.0 is directly connected, Serial0/0
3.0.0.0/24 is subnetted, 1 subnets
O E2 3.3.3.0 [110/12] via 4.4.4.2, 00:04:43, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
C 4.4.4.0 is directly connected, Serial0/1
10.0.0.0/16 is subnetted, 7 subnets
C 10.10.0.0 is directly connected, Loopback3
C 10.11.0.0 is directly connected, Loopback4
C 10.8.0.0 is directly connected, Loopback1
C 10.9.0.0 is directly connected, Loopback2
O E2 10.2.0.0 [110/12] via 2.2.2.2, 00:05:06, Serial0/0
O E2 10.3.0.0 [110/12] via 2.2.2.2, 00:05:06, Serial0/0
O E2 10.1.0.0 [110/12] via 2.2.2.2, 00:05:06, Serial0/0
r3#
可以看到R3是**R2来学习RIP网络的路由的！！！
R4:
r4#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
O E2 1.1.1.0 [110/12] via 4.4.4.1, 00:05:50, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
O 2.2.2.0 [110/128] via 4.4.4.1, 00:05:50, Serial0/0
3.0.0.0/24 is subnetted, 1 subnets
C 3.3.3.0 is directly connected, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
C 4.4.4.0 is directly connected, Serial0/0
10.0.0.0/8 is variably subnetted, 7 subnets, 2 masks
O 10.10.10.10/32 [110/65] via 4.4.4.1, 00:05:50, Serial0/0
O 10.11.11.11/32 [110/65] via 4.4.4.1, 00:05:50, Serial0/0
O 10.8.8.8/32 [110/65] via 4.4.4.1, 00:05:50, Serial0/0
O 10.9.9.9/32 [110/65] via 4.4.4.1, 00:05:50, Serial0/0
O E2 10.2.0.0/16 [110/12] via 4.4.4.1, 00:05:51, Serial0/0
O E2 10.3.0.0/16 [110/12] via 4.4.4.1, 00:05:51, Serial0/0
O E2 10.1.0.0/16 [110/12] via 4.4.4.1, 00:05:51, Serial0/0
r4#
如上面，R4是**OSPF学习到的RIP网络的路由，因为OSPF的AD值比RIP小，所以OSPF的路由信息被装进路由表，而这并不**优的路由，这就是大AD值在重发布进小AD值时遇到的次优路径。下面配置分发列表来解决这个问题：
配置参数：
R2:
r2(config)#acc 1 de 10.1.0.0 //配置不匹配RIP网络的路由
r2(config)#acc 1 de 10.2.0.0
r2(config)#acc 1 de 10.3.0.0
r2(config)#acc 1 per an //配置匹配其它的路由
r2(config)#router os 1 //进入OSPF路由配置进程
r2(config-router)#distribute-list 1 in s0/1 //配置分发列表，只有访问列表1匹配的路由才可以从接口s0/1进入
R4:
r4(config)#acc 1 de 10.1.0.0
r4(config)#acc 1 de 10.2.0.0
r4(config)#acc 1 de 10.3.0.0
r4(config)#acc 1 per an
r4(config)#router os 1
r4(config-router)#distri 1 in s0/0
r4(config-router)#
查看配置效果：
R2:
r2#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
C 1.1.1.0 is directly connected, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
C 2.2.2.0 is directly connected, Serial0/1
3.0.0.0/24 is subnetted, 1 subnets
O E2 3.3.3.0 [110/12] via 2.2.2.1, 00:05:08, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
O 4.4.4.0 [110/128] via 2.2.2.1, 00:05:08, Serial0/1
10.0.0.0/8 is variably subnetted, 7 subnets, 2 masks
O 10.10.10.10/32 [110/65] via 2.2.2.1, 00:05:08, Serial0/1
O 10.11.11.11/32 [110/65] via 2.2.2.1, 00:05:08, Serial0/1
O 10.8.8.8/32 [110/65] via 2.2.2.1, 00:05:08, Serial0/1
O 10.9.9.9/32 [110/65] via 2.2.2.1, 00:05:08, Serial0/1
R 10.2.0.0/16 [120/1] via 1.1.1.1, 00:00:42, Serial0/0
R 10.3.0.0/16 [120/1] via 1.1.1.1, 00:00:42, Serial0/0
R 10.1.0.0/16 [120/1] via 1.1.1.1, 00:00:42, Serial0/0
r2#
可以看出R2**RIP学习到了RIP网络的路由
R3:
r3#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
O E2 1.1.1.0 [110/12] via 2.2.2.2, 00:03:36, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
C 2.2.2.0 is directly connected, Serial0/0
3.0.0.0/24 is subnetted, 1 subnets
O E2 3.3.3.0 [110/12] via 4.4.4.2, 00:15:00, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
C 4.4.4.0 is directly connected, Serial0/1
10.0.0.0/16 is subnetted, 7 subnets
C 10.10.0.0 is directly connected, Loopback3
C 10.11.0.0 is directly connected, Loopback4
C 10.8.0.0 is directly connected, Loopback1
C 10.9.0.0 is directly connected, Loopback2
O E2 10.2.0.0 [110/12] via 4.4.4.2, 00:03:49, Serial0/1
[110/12] via 2.2.2.2, 00:03:49, Serial0/0
O E2 10.3.0.0 [110/12] via 4.4.4.2, 00:03:49, Serial0/1
[110/12] via 2.2.2.2, 00:03:49, Serial0/0
O E2 10.1.0.0 [110/12] via 4.4.4.2, 00:03:49, Serial0/1
[110/12] via 2.2.2.2, 00:03:49, Serial0/0
r3#
可以看到R3的路由表中，RIP网络的路由是**R2和R4学习到的而且实现了负载均衡，和R1学习到OSPF网络的路由一样，可以看到有2条路由去往对端的网络！！！
R4:
r4#sh ip rou
1.0.0.0/24 is subnetted, 1 subnets
O E2 1.1.1.0 [110/12] via 4.4.4.1, 00:06:17, Serial0/0
2.0.0.0/24 is subnetted, 1 subnets
O 2.2.2.0 [110/128] via 4.4.4.1, 00:06:17, Serial0/0
3.0.0.0/24 is subnetted, 1 subnets
C 3.3.3.0 is directly connected, Serial0/1
4.0.0.0/24 is subnetted, 1 subnets
C 4.4.4.0 is directly connected, Serial0/0
10.0.0.0/8 is variably subnetted, 7 subnets, 2 masks
O 10.10.10.10/32 [110/65] via 4.4.4.1, 00:06:17, Serial0/0
O 10.11.11.11/32 [110/65] via 4.4.4.1, 00:06:17, Serial0/0
O 10.8.8.8/32 [110/65] via 4.4.4.1, 00:06:17, Serial0/0
O 10.9.9.9/32 [110/65] via 4.4.4.1, 00:06:17, Serial0/0
R 10.2.0.0/16 [120/1] via 3.3.3.1, 00:00:21, Serial0/1
R 10.3.0.0/16 [120/1] via 3.3.3.1, 00:00:21, Serial0/1
R 10.1.0.0/16 [120/1] via 3.3.3.1, 00:00:21, Serial0/1
r4#
可以看到R4是**RIP学习到的RIP网络的路由，而不是**OSPF，这样避免了次优路径！
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